内容简介：Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array.Example:For num = 5 you should return [0,1,1,2,1,2].
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array.
Example:
For num = 5 you should return [0,1,1,2,1,2].
Follow up:
It is very easy to come up with a solution with run time O(n*sizeof(integer)). But can you do it in linear time O(n) /possibly in a single pass?
Space complexity should be O(n).
Can you do it like a boss? Do it without using any builtin function like __builtin_popcount in c++ or in any other language.
func countBits(_ num: Int) -> [Int] {
var arr = Array(repeating: 0, count: num+1), i = 0
while i <= num {
arr[i] = i.nonzeroBitCount
i += 1
}
return arr
}
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