c++ 计算两个数字之间的差距的最短方法？

我要在C中这样做,但是我不得不用多种语言来做,这是一个相当普遍和简单的问题,这是最后一次.我已经有足够的编码,我确定必须有一个更好的方法,所以我发布在这里之前,我用另一种语言写出相同的长风方法;

考虑(百合！)以下代码;

// I want the difference between these two values as a positive integer
int x = 7
int y = 3
int diff;
// This means you have to find the largest number first 
// before making the subtract, to keep the answer positive
if (x>y) { 
     diff = (x-y);
} else if (y>x) {
     diff = (y-x);
} else if (x==y) {
    diff = 0;
}

这可能听起来很小,但对我来说似乎很多,只是为了获得两个数字之间的区别.这实际上是一个完全合理的做事方式,我是不必要的迂腐的,还是我的强烈的感觉刺激了很好的理由？

#include <cstdlib>
int diff = std::abs(x-y);