内容简介：翻译自：https://stackoverflow.com/questions/15443040/how-to-url-encode-a-nsstring
我试图url编码一个字符串,但NSURLConnection失败,因为’坏网址’.这是我的网址：
NSString *address = mp.streetAddress;
NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *cityState= mp.cityState;
NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", encodedAddress, encodedCityState];
NSURL *url = [NSURL URLWithString:fullAddressURL];
以下是API调用URL的示例：
下面是调用API的地址匹配“2114 Bigelow Ave”,“Seattle,WA”的地址的示例：
http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA
由于某种原因,此URL无法连接.有人可以帮我吗？
您必须先编码fullAddressURL,然后再将其发送到NSURL,而不是编码地址& cityState个别.
NSString *address = @"2114 Bigelow Ave"; //NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; NSString *cityState= @"Seattle, WA"; // NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", address, cityState]; fullAddressURL = [fullAddressURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; NSLog(@"fullAddressURL: %@",fullAddressURL); NSURL *url = [NSURL URLWithString:fullAddressURL];
我测试了上面的代码,它给出了与给定链接相同的输出http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=\u0026lt;ZWSID\u0026gt;\u0026amp;address=2114 Bigelow Ave& citystatezip = Seattle ,华盛顿州
翻译自：https://stackoverflow.com/questions/15443040/how-to-url-encode-a-nsstring
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