云发购 Go 同步发HTTP请求是不是要比Python慢很多？

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Go 新手，最近想测试下用 Go 发HTTP的速度，所以就写了个脚本测试了下，同时发两个请求，跟 Python 对比了下，发现慢了很多， Python 使用aiohttp耗时0.14s，Go版本的耗时 0.29s，慢了2倍

按理讲如果Go的速度不快的话，那至少也是跟Python差不多的嘛， 为什么会差这么多，是我写的方式不对吗？求指教。

Go 和 Python 代码如下：

import time

import aiohttp

import asyncio

async def fetch(session, url):

async with session.post(url) as response:

return await response.text()

async def main(url):

async with aiohttp.ClientSession() as session:

html = await fetch(session, url)

return html

if name == ' main ':

t = time.time()

loop = asyncio.get_event_loop()

urls = [

" https://sina.com.cn ",

" https://news.baidu.com "

]

tasks = [main(url) for url in urls]

responses = loop.run_until_complete(asyncio.gather(*tasks))

for response in responses:
    print(response)

print(time.time() - t)

package main

import (

"fmt"

"io/ioutil"

"net/http"

"time"

)

func MakeRequest(client http.Client, url string, ch chan<- string) {

reqest, _ := http.NewRequest("GET", url, nil)

response, _ := client.Do(reqest)
body, _ := ioutil.ReadAll(response.Body)
ch <- string(body)

}

func main() {

start := time.Now()

urls := []string{" https://sina.com.cn ", " https://news.baidu.com "}

client := &http.Client{}

ch := make(chan string)

for _, url := range urls {

go MakeRequest(*client, url, ch)

}

for range urls {
    fmt.Println(<-ch)
}

fmt.Printf("%.8fs elapsed\n", time.Since(start).Seconds())

}

第 1 条附言 · 2018-07-04 15:22:29

使用buffered channel，不过还是比Python慢

package main

import (

"fmt"

"io/ioutil"

"net/http"

"time"

)

func MakeRequest(client http.Client, url string, ch chan<- string) {

reqest, _ := http.NewRequest("GET", url, nil)

response, _ := client.Do(reqest)
body, _ := ioutil.ReadAll(response.Body)
ch <- string(body)

}

func main() {

start := time.Now()

urls := []string{" https://sina.com.cn ", " https://news.baidu.com "}

client := &http.Client{}

ch := make(chan string, len(urls))

for _, url := range urls {

go MakeRequest(*client, url, ch)

}

for range urls {
    fmt.Println(<-ch)
}

fmt.Printf("%.8fs elapsed\n", time.Since(start).Seconds())

}