内容简介:Given an encoded string, return it’s decoded string.The encoding rule is:You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc.
Given an encoded string, return it’s decoded string.
The encoding rule is: k[encoded_string]
, where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer.
You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc.
Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k . For example, there won’t be input like 3a
or 2[4]
.
Examples:
s = "3[a]2[bc]", return "aaabcbc". s = "3[a2[c]]", return "accaccacc". s = "2[abc]3[cd]ef", return "abcabccdcdcdef".
func decodeString(_ s: String) -> String { var stack = [String]() s.forEach { switch $0 { case "]": var s = "", i = "" while let c = stack.popLast(), c != "[" { s = "\(c)\(s)" } while let sl = stack.last, nil != Int("\(sl)"), let c = stack.popLast() { i = "\(c)\(i)" } stack.append(String(repeating: s, count: Int(i)!)) default: stack.append(String($0)) } } return stack.joined() }
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以上所述就是小编给大家介绍的《[swift] LeetCode 394. Decode String》,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对 码农网 的支持!
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构建高性能Web站点
郭欣 / 电子工业出版社 / 2012-6 / 75.00元
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