173. Binary Search Tree Iterator

栏目: 编程工具 · 发布时间: 4年前

内容简介:Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.Calling next() will return the next smallest number in the BST.Example:

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.

Calling next() will return the next smallest number in the BST.

Example:

173. Binary Search Tree Iterator

BSTIterator iterator = new BSTIterator(root);
iterator.next();    // return 3
iterator.next();    // return 7
iterator.hasNext(); // return true
iterator.next();    // return 9
iterator.hasNext(); // return true
iterator.next();    // return 15
iterator.hasNext(); // return true
iterator.next();    // return 20
iterator.hasNext(); // return false

Note:

next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.

You may assume that next() call will always be valid, that is, there will be at least a next smallest number in the BST when next() is called.

难度:medium

题目:实现二叉搜索树的遍历。迭代器用根结点初始化。调用next()将会返回下一个最小的结点。

Runtime: 76 ms, faster than 37.23% of Java online submissions for Binary Search Tree Iterator.

Memory Usage: 52.1 MB, less than 100.00% of Java online submissions for Binary Search Tree Iterator.

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class BSTIterator {
    private Stack<TreeNode> stack;
    
    public BSTIterator(TreeNode root) {
        stack = new Stack<>();
        while (root != null) {
            stack.push(root);
            root = root.left;
        }
    }
    
    /** @return the next smallest number */
    public int next() {
        TreeNode node = stack.pop();
        TreeNode ptr = node.right;
        while (ptr != null) {
            stack.push(ptr);
            ptr = ptr.left;
        }
        
        return node.val;
    }
    
    /** @return whether we have a next smallest number */
    public boolean hasNext() {
        return !stack.isEmpty();
    }
}

/**
 * Your BSTIterator object will be instantiated and called as such:
 * BSTIterator obj = new BSTIterator(root);
 * int param_1 = obj.next();
 * boolean param_2 = obj.hasNext();
 */

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